Base | Representation |
---|---|
bin | 11100000010101100001000… |
… | …100101101110011111110011 |
3 | 121011200020121210220112122111 |
4 | 130002230020211232133303 |
5 | 112131120101240342042 |
6 | 1114145025104150151 |
7 | 34656210410223622 |
oct | 3402541045563763 |
9 | 534606553815574 |
10 | 123330130012147 |
11 | 3632a018200273 |
12 | 119ba257008357 |
13 | 53a7c9b071716 |
14 | 22652d28b76b9 |
15 | e3d1767b4517 |
hex | 702b0896e7f3 |
123330130012147 has 2 divisors, whose sum is σ = 123330130012148. Its totient is φ = 123330130012146.
The previous prime is 123330130012097. The next prime is 123330130012183. The reversal of 123330130012147 is 741210031033321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 123330130012147 - 211 = 123330130010099 is a prime.
It is not a weakly prime, because it can be changed into another prime (123330130012547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61665065006073 + 61665065006074.
It is an arithmetic number, because the mean of its divisors is an integer number (61665065006074).
Almost surely, 2123330130012147 is an apocalyptic number.
123330130012147 is a deficient number, since it is larger than the sum of its proper divisors (1).
123330130012147 is an equidigital number, since it uses as much as digits as its factorization.
123330130012147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9072, while the sum is 31.
Adding to 123330130012147 its reverse (741210031033321), we get a palindrome (864540161045468).
The spelling of 123330130012147 in words is "one hundred twenty-three trillion, three hundred thirty billion, one hundred thirty million, twelve thousand, one hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.340 sec. • engine limits •