Base | Representation |
---|---|
bin | 10001111100100111001… |
… | …001000100010000110011 |
3 | 11100220101122200101200021 |
4 | 101330213021010100303 |
5 | 130201310422132011 |
6 | 2342324214504311 |
7 | 155050425412300 |
oct | 21744711042063 |
9 | 4326348611607 |
10 | 1233312302131 |
11 | 4360547077a8 |
12 | 17b035965097 |
13 | 8c3bac7b7a0 |
14 | 4399a8320a7 |
15 | 221344e7471 |
hex | 11f27244433 |
1233312302131 has 24 divisors (see below), whose sum is σ = 1547395167024. Its totient is φ = 974312861760.
The previous prime is 1233312302087. The next prime is 1233312302153. The reversal of 1233312302131 is 1312032133321.
It is not a de Polignac number, because 1233312302131 - 217 = 1233312171059 is a prime.
It is a super-2 number, since 2×12333123021312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1233312302096 and 1233312302105.
It is not an unprimeable number, because it can be changed into a prime (1233312302171) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1066525 + ... + 1898446.
It is an arithmetic number, because the mean of its divisors is an integer number (64474798626).
Almost surely, 21233312302131 is an apocalyptic number.
1233312302131 is a deficient number, since it is larger than the sum of its proper divisors (314082864893).
1233312302131 is a wasteful number, since it uses less digits than its factorization.
1233312302131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2965651 (or 2965644 counting only the distinct ones).
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 1233312302131 its reverse (1312032133321), we get a palindrome (2545344435452).
The spelling of 1233312302131 in words is "one trillion, two hundred thirty-three billion, three hundred twelve million, three hundred two thousand, one hundred thirty-one".
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