Base | Representation |
---|---|
bin | 10110111110001110… |
… | …11100010101001001 |
3 | 1011211112002201102022 |
4 | 23133013130111021 |
5 | 200224300023214 |
6 | 5355451214225 |
7 | 614425340222 |
oct | 133707342511 |
9 | 34745081368 |
10 | 12333204809 |
11 | 5259855352 |
12 | 2482447375 |
13 | 12171ba233 |
14 | 84dd96249 |
15 | 4c2b3cd8e |
hex | 2df1dc549 |
12333204809 has 2 divisors, whose sum is σ = 12333204810. Its totient is φ = 12333204808.
The previous prime is 12333204799. The next prime is 12333204869. The reversal of 12333204809 is 90840233321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9952057600 + 2381147209 = 99760^2 + 48797^2 .
It is an emirp because it is prime and its reverse (90840233321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12333204809 - 232 = 8038237513 is a prime.
It is not a weakly prime, because it can be changed into another prime (12333204869) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6166602404 + 6166602405.
It is an arithmetic number, because the mean of its divisors is an integer number (6166602405).
Almost surely, 212333204809 is an apocalyptic number.
It is an amenable number.
12333204809 is a deficient number, since it is larger than the sum of its proper divisors (1).
12333204809 is an equidigital number, since it uses as much as digits as its factorization.
12333204809 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 35.
The spelling of 12333204809 in words is "twelve billion, three hundred thirty-three million, two hundred four thousand, eight hundred nine".
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