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12333304141 = 24115115431
BaseRepresentation
bin10110111110001111…
…10100100101001101
31011211112021202200021
423133013310211031
5200224311213031
65355453302141
7614426232634
oct133707644515
934745252607
1012333304141
115259912a44
122482494951
131217223502
1484ddc051b
154c2b5c511
hex2df1f494d

12333304141 has 4 divisors (see below), whose sum is σ = 12338421984. Its totient is φ = 12328186300.

The previous prime is 12333304133. The next prime is 12333304183. The reversal of 12333304141 is 14140333321.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12333304141 - 23 = 12333304133 is a prime.

It is a super-2 number, since 2×123333041412 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12333004141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2555305 + ... + 2560126.

It is an arithmetic number, because the mean of its divisors is an integer number (3084605496).

Almost surely, 212333304141 is an apocalyptic number.

It is an amenable number.

12333304141 is a deficient number, since it is larger than the sum of its proper divisors (5117843).

12333304141 is an equidigital number, since it uses as much as digits as its factorization.

12333304141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5117842.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 12333304141 its reverse (14140333321), we get a palindrome (26473637462).

The spelling of 12333304141 in words is "twelve billion, three hundred thirty-three million, three hundred four thousand, one hundred forty-one".

Divisors: 1 2411 5115431 12333304141