Base | Representation |
---|---|
bin | 1011001101111011110010… |
… | …0001111100010000101001 |
3 | 1121200010020122120111201212 |
4 | 2303132330201330100221 |
5 | 3104040030103333001 |
6 | 42122100131522505 |
7 | 2412050240132366 |
oct | 263367441742051 |
9 | 47603218514655 |
10 | 12334014121001 |
11 | 3a2590a473701 |
12 | 14724b8459435 |
13 | 6b612840a4c1 |
14 | 308d8031746d |
15 | 165c8181c7bb |
hex | b37bc87c429 |
12334014121001 has 2 divisors, whose sum is σ = 12334014121002. Its totient is φ = 12334014121000.
The previous prime is 12334014120997. The next prime is 12334014121007. The reversal of 12334014121001 is 10012141043321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11497016025625 + 836998095376 = 3390725^2 + 914876^2 .
It is a cyclic number.
It is not a de Polignac number, because 12334014121001 - 22 = 12334014120997 is a prime.
It is not a weakly prime, because it can be changed into another prime (12334014121007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6167007060500 + 6167007060501.
It is an arithmetic number, because the mean of its divisors is an integer number (6167007060501).
Almost surely, 212334014121001 is an apocalyptic number.
It is an amenable number.
12334014121001 is a deficient number, since it is larger than the sum of its proper divisors (1).
12334014121001 is an equidigital number, since it uses as much as digits as its factorization.
12334014121001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 12334014121001 its reverse (10012141043321), we get a palindrome (22346155164322).
The spelling of 12334014121001 in words is "twelve trillion, three hundred thirty-four billion, fourteen million, one hundred twenty-one thousand, one".
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