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12334402019 is a prime number
BaseRepresentation
bin10110111110011000…
…00000100111100011
31011211121100112200102
423133030000213203
5200230101331034
65355533013015
7614441454512
oct133714004743
934747315612
1012334402019
11525a4a2885
12248292416b
131217519144
148501c8679
154c2cc797e
hex2df3009e3

12334402019 has 2 divisors, whose sum is σ = 12334402020. Its totient is φ = 12334402018.

The previous prime is 12334401991. The next prime is 12334402033. The reversal of 12334402019 is 91020443321.

12334402019 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12334402019 is a prime.

It is a super-2 number, since 2×123344020192 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12334401982 and 12334402000.

It is not a weakly prime, because it can be changed into another prime (12334402039) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6167201009 + 6167201010.

It is an arithmetic number, because the mean of its divisors is an integer number (6167201010).

Almost surely, 212334402019 is an apocalyptic number.

12334402019 is a deficient number, since it is larger than the sum of its proper divisors (1).

12334402019 is an equidigital number, since it uses as much as digits as its factorization.

12334402019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 29.

The spelling of 12334402019 in words is "twelve billion, three hundred thirty-four million, four hundred two thousand, nineteen".