Base | Representation |
---|---|
bin | 11100000010111010010001… |
… | …100101100101001100110000 |
3 | 121011201200210222001020211012 |
4 | 130002322101211211030300 |
5 | 112131342200204321134 |
6 | 1114200015452010052 |
7 | 34660255564422161 |
oct | 3402722145451460 |
9 | 534650728036735 |
10 | 123345313354544 |
11 | 363354a9868126 |
12 | 11a01193a60928 |
13 | 53a954a891aa8 |
14 | 2265d331c5768 |
15 | e3d7647426ce |
hex | 702e91965330 |
123345313354544 has 20 divisors (see below), whose sum is σ = 244539254965896. Its totient is φ = 60238408847232.
The previous prime is 123345313354531. The next prime is 123345313354607. The reversal of 123345313354544 is 445453313543321.
It is a happy number.
123345313354544 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 123345313354492 and 123345313354501.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89640488669 + ... + 89640490044.
Almost surely, 2123345313354544 is an apocalyptic number.
It is an amenable number.
123345313354544 is a deficient number, since it is larger than the sum of its proper divisors (121193941611352).
123345313354544 is a wasteful number, since it uses less digits than its factorization.
123345313354544 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 179280978764 (or 179280978758 counting only the distinct ones).
The product of its digits is 15552000, while the sum is 50.
Adding to 123345313354544 its reverse (445453313543321), we get a palindrome (568798626897865).
The spelling of 123345313354544 in words is "one hundred twenty-three trillion, three hundred forty-five billion, three hundred thirteen million, three hundred fifty-four thousand, five hundred forty-four".
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