Base | Representation |
---|---|
bin | 11100000010111010011000… |
… | …100011110100111110101011 |
3 | 121011201201010010011111101121 |
4 | 130002322120203310332223 |
5 | 112131342420131213103 |
6 | 1114200035231200111 |
7 | 34660261514640223 |
oct | 3402723043647653 |
9 | 534651103144347 |
10 | 123345430335403 |
11 | 363355598a7621 |
12 | 11a01207076037 |
13 | 53a9568b9c733 |
14 | 2265d44957083 |
15 | e3d76eb4d6bd |
hex | 702e988f4fab |
123345430335403 has 2 divisors, whose sum is σ = 123345430335404. Its totient is φ = 123345430335402.
The previous prime is 123345430335383. The next prime is 123345430335497. The reversal of 123345430335403 is 304533034543321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 123345430335403 - 213 = 123345430327211 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 123345430335403.
It is not a weakly prime, because it can be changed into another prime (123345433335403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61672715167701 + 61672715167702.
It is an arithmetic number, because the mean of its divisors is an integer number (61672715167702).
Almost surely, 2123345430335403 is an apocalyptic number.
123345430335403 is a deficient number, since it is larger than the sum of its proper divisors (1).
123345430335403 is an equidigital number, since it uses as much as digits as its factorization.
123345430335403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2332800, while the sum is 43.
Adding to 123345430335403 its reverse (304533034543321), we get a palindrome (427878464878724).
The spelling of 123345430335403 in words is "one hundred twenty-three trillion, three hundred forty-five billion, four hundred thirty million, three hundred thirty-five thousand, four hundred three".
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