Base | Representation |
---|---|
bin | 1011001110010100110110… |
… | …1001010001001001101001 |
3 | 1121200202121122110210202211 |
4 | 2303211031221101021221 |
5 | 3104142320342031233 |
6 | 42125132010125121 |
7 | 2412406063506361 |
oct | 263451551211151 |
9 | 47622548423684 |
10 | 12340743705193 |
11 | 3a2875310a932 |
12 | 14738761207a1 |
13 | 6b695b6a3297 |
14 | 30941bda19a1 |
15 | 16602751d5cd |
hex | b394da51269 |
12340743705193 has 2 divisors, whose sum is σ = 12340743705194. Its totient is φ = 12340743705192.
The previous prime is 12340743705109. The next prime is 12340743705221. The reversal of 12340743705193 is 39150734704321.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8032848355984 + 4307895349209 = 2834228^2 + 2075547^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12340743705193 is a prime.
It is not a weakly prime, because it can be changed into another prime (12340743709193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6170371852596 + 6170371852597.
It is an arithmetic number, because the mean of its divisors is an integer number (6170371852597).
Almost surely, 212340743705193 is an apocalyptic number.
It is an amenable number.
12340743705193 is a deficient number, since it is larger than the sum of its proper divisors (1).
12340743705193 is an equidigital number, since it uses as much as digits as its factorization.
12340743705193 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1905120, while the sum is 49.
The spelling of 12340743705193 in words is "twelve trillion, three hundred forty billion, seven hundred forty-three million, seven hundred five thousand, one hundred ninety-three".
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