Base | Representation |
---|---|
bin | 11100000011110111100100… |
… | …100100100101011000111111 |
3 | 121011221222200211212221010010 |
4 | 130003313210210211120333 |
5 | 112133431443302032201 |
6 | 1114250142425314303 |
7 | 34665105564552132 |
oct | 3403674444453077 |
9 | 534858624787103 |
10 | 123411130111551 |
11 | 36360403698887 |
12 | 11a11aa1935993 |
13 | 53b2809449a19 |
14 | 22691b83c8219 |
15 | e40317983bd6 |
hex | 703de492563f |
123411130111551 has 16 divisors (see below), whose sum is σ = 164827124352000. Its totient is φ = 82134618385248.
The previous prime is 123411130111517. The next prime is 123411130111573. The reversal of 123411130111551 is 155111031114321.
It is not a de Polignac number, because 123411130111551 - 223 = 123411121722943 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (123411130111751) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 70492330 + ... + 72221816.
It is an arithmetic number, because the mean of its divisors is an integer number (10301695272000).
Almost surely, 2123411130111551 is an apocalyptic number.
123411130111551 is a deficient number, since it is larger than the sum of its proper divisors (41415994240449).
123411130111551 is a wasteful number, since it uses less digits than its factorization.
123411130111551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1769798.
The product of its (nonzero) digits is 1800, while the sum is 30.
Adding to 123411130111551 its reverse (155111031114321), we get a palindrome (278522161225872).
The spelling of 123411130111551 in words is "one hundred twenty-three trillion, four hundred eleven billion, one hundred thirty million, one hundred eleven thousand, five hundred fifty-one".
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