Base | Representation |
---|---|
bin | 1011001110011101010000… |
… | …1000011101110000011010 |
3 | 1121200222102220010222211221 |
4 | 2303213110020131300122 |
5 | 3104211431001431414 |
6 | 42130143531042254 |
7 | 2412516022115446 |
oct | 263472410356032 |
9 | 47628386128757 |
10 | 12343000030234 |
11 | 3a29700810275 |
12 | 14741a58a038a |
13 | 6b6c2ac95c63 |
14 | 309593901826 |
15 | 16610a664224 |
hex | b39d421dc1a |
12343000030234 has 4 divisors (see below), whose sum is σ = 18514500045354. Its totient is φ = 6171500015116.
The previous prime is 12343000030223. The next prime is 12343000030247. The reversal of 12343000030234 is 43203000034321.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 9136382796025 + 3206617234209 = 3022645^2 + 1790703^2 .
It is a junction number, because it is equal to n+sod(n) for n = 12343000030199 and 12343000030208.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3085750007557 + ... + 3085750007560.
Almost surely, 212343000030234 is an apocalyptic number.
12343000030234 is a deficient number, since it is larger than the sum of its proper divisors (6171500015120).
12343000030234 is an equidigital number, since it uses as much as digits as its factorization.
12343000030234 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6171500015119.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 12343000030234 its reverse (43203000034321), we get a palindrome (55546000064555).
The spelling of 12343000030234 in words is "twelve trillion, three hundred forty-three billion, thirty thousand, two hundred thirty-four".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •