Base | Representation |
---|---|
bin | 10001111101100100011… |
… | …101101111010000100011 |
3 | 11101000001100121022222021 |
4 | 101331210131233100203 |
5 | 130210412312200144 |
6 | 2343014250122311 |
7 | 155115060334243 |
oct | 21754435572043 |
9 | 4330040538867 |
10 | 1234341131299 |
11 | 436532431341 |
12 | 17b282420397 |
13 | 8c523170a43 |
14 | 43a57325b23 |
15 | 221949c0884 |
hex | 11f6476f423 |
1234341131299 has 2 divisors, whose sum is σ = 1234341131300. Its totient is φ = 1234341131298.
The previous prime is 1234341131249. The next prime is 1234341131327. The reversal of 1234341131299 is 9921311434321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1234341131299 - 215 = 1234341098531 is a prime.
It is not a weakly prime, because it can be changed into another prime (1234341131239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 617170565649 + 617170565650.
It is an arithmetic number, because the mean of its divisors is an integer number (617170565650).
Almost surely, 21234341131299 is an apocalyptic number.
1234341131299 is a deficient number, since it is larger than the sum of its proper divisors (1).
1234341131299 is an equidigital number, since it uses as much as digits as its factorization.
1234341131299 is an evil number, because the sum of its binary digits is even.
The product of its digits is 139968, while the sum is 43.
The spelling of 1234341131299 in words is "one trillion, two hundred thirty-four billion, three hundred forty-one million, one hundred thirty-one thousand, two hundred ninety-nine".
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