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1234420123 is a prime number
BaseRepresentation
bin100100110010011…
…1100000110011011
310012000210001001211
41021210330012123
510012002420443
6322253523551
742406253326
oct11144740633
93160701054
101234420123
11583886122
122a54a35b7
13168986311
14b9d2d7bd
157358919d
hex4993c19b

1234420123 has 2 divisors, whose sum is σ = 1234420124. Its totient is φ = 1234420122.

The previous prime is 1234420091. The next prime is 1234420141. The reversal of 1234420123 is 3210244321.

It is a strong prime.

It is an emirp because it is prime and its reverse (3210244321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1234420123 - 25 = 1234420091 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1234420094 and 1234420103.

It is not a weakly prime, because it can be changed into another prime (1234420153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 617210061 + 617210062.

It is an arithmetic number, because the mean of its divisors is an integer number (617210062).

Almost surely, 21234420123 is an apocalyptic number.

1234420123 is a deficient number, since it is larger than the sum of its proper divisors (1).

1234420123 is an equidigital number, since it uses as much as digits as its factorization.

1234420123 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 22.

The square root of 1234420123 is about 35134.3154622372. The cubic root of 1234420123 is about 1072.7231776921.

Adding to 1234420123 its reverse (3210244321), we get a palindrome (4444664444).

The spelling of 1234420123 in words is "one billion, two hundred thirty-four million, four hundred twenty thousand, one hundred twenty-three".