Base | Representation |
---|---|
bin | 1011001110101111111101… |
… | …1011001110110101000011 |
3 | 1121201110101211121211100211 |
4 | 2303223333123032311003 |
5 | 3104302221430244121 |
6 | 42132334103054551 |
7 | 2413054323405124 |
oct | 263537733166503 |
9 | 47643354554324 |
10 | 12348021337411 |
11 | 3a30848150711 |
12 | 1475167441457 |
13 | 6b754b374c36 |
14 | 30990c74c04b |
15 | 1663013c8ce1 |
hex | b3aff6ced43 |
12348021337411 has 2 divisors, whose sum is σ = 12348021337412. Its totient is φ = 12348021337410.
The previous prime is 12348021337313. The next prime is 12348021337417. The reversal of 12348021337411 is 11473312084321.
It is a strong prime.
It is an emirp because it is prime and its reverse (11473312084321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12348021337411 - 213 = 12348021329219 is a prime.
It is a super-2 number, since 2×123480213374112 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12348021337417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6174010668705 + 6174010668706.
It is an arithmetic number, because the mean of its divisors is an integer number (6174010668706).
Almost surely, 212348021337411 is an apocalyptic number.
12348021337411 is a deficient number, since it is larger than the sum of its proper divisors (1).
12348021337411 is an equidigital number, since it uses as much as digits as its factorization.
12348021337411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96768, while the sum is 40.
The spelling of 12348021337411 in words is "twelve trillion, three hundred forty-eight billion, twenty-one million, three hundred thirty-seven thousand, four hundred eleven".
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