Base | Representation |
---|---|
bin | 1011001110111011000110… |
… | …1100000110000000000111 |
3 | 1121201202010021021102022021 |
4 | 2303232301230012000013 |
5 | 3104324333044232101 |
6 | 42133550541344011 |
7 | 2413221410444632 |
oct | 263566154060007 |
9 | 47652107242267 |
10 | 12351012102151 |
11 | 3a32042383508 |
12 | 1475860b68007 |
13 | 6b7906b74a08 |
14 | 309b13a2cc19 |
15 | 166428c465a1 |
hex | b3bb1b06007 |
12351012102151 has 4 divisors (see below), whose sum is σ = 12351295211632. Its totient is φ = 12350728992672.
The previous prime is 12351012102109. The next prime is 12351012102181. The reversal of 12351012102151 is 15120121015321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12351012102151 - 217 = 12351011971079 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12351012102181) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 141489291 + ... + 141576556.
It is an arithmetic number, because the mean of its divisors is an integer number (3087823802908).
Almost surely, 212351012102151 is an apocalyptic number.
12351012102151 is a deficient number, since it is larger than the sum of its proper divisors (283109481).
12351012102151 is an equidigital number, since it uses as much as digits as its factorization.
12351012102151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 283109480.
The product of its (nonzero) digits is 600, while the sum is 25.
Adding to 12351012102151 its reverse (15120121015321), we get a palindrome (27471133117472).
The spelling of 12351012102151 in words is "twelve trillion, three hundred fifty-one billion, twelve million, one hundred two thousand, one hundred fifty-one".
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