Base | Representation |
---|---|
bin | 111001100000111100… |
… | …1010111010000010010 |
3 | 102210210202212000111012 |
4 | 1303001321113100102 |
5 | 4010423100440214 |
6 | 132423553250522 |
7 | 11631513510146 |
oct | 1630171272022 |
9 | 383722760435 |
10 | 123512124434 |
11 | 484214131a6 |
12 | 1bb2bb63a42 |
13 | b854a0a4ca |
14 | 5d9997d226 |
15 | 332d4aa03e |
hex | 1cc1e57412 |
123512124434 has 4 divisors (see below), whose sum is σ = 185268186654. Its totient is φ = 61756062216.
The previous prime is 123512124419. The next prime is 123512124443. The reversal of 123512124434 is 434421215321.
123512124434 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 71275650625 + 52236473809 = 266975^2 + 228553^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 123512124434.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30878031107 + ... + 30878031110.
Almost surely, 2123512124434 is an apocalyptic number.
123512124434 is a deficient number, since it is larger than the sum of its proper divisors (61756062220).
123512124434 is an equidigital number, since it uses as much as digits as its factorization.
123512124434 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61756062219.
The product of its digits is 23040, while the sum is 32.
Adding to 123512124434 its reverse (434421215321), we get a palindrome (557933339755).
The spelling of 123512124434 in words is "one hundred twenty-three billion, five hundred twelve million, one hundred twenty-four thousand, four hundred thirty-four".
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