Search a number
-
+
123519857556457 is a prime number
BaseRepresentation
bin11100000101011100110101…
…001110110111101111101001
3121012100101100020202102002001
4130011130311032313233221
5112142222132013301312
61114412123400011001
735006005134566335
oct3405346516675751
9535311306672061
10123519857556457
11363a252848646a
1211a2ab86460a61
1353bcb460ca93b
1422705705927c5
15e4307cead057
hex7057353b7be9

123519857556457 has 2 divisors, whose sum is σ = 123519857556458. Its totient is φ = 123519857556456.

The previous prime is 123519857556383. The next prime is 123519857556493. The reversal of 123519857556457 is 754655758915321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 80119971352576 + 43399886203881 = 8950976^2 + 6587859^2 .

It is a cyclic number.

It is not a de Polignac number, because 123519857556457 - 211 = 123519857554409 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 123519857556457.

It is not a weakly prime, because it can be changed into another prime (123519857556497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61759928778228 + 61759928778229.

It is an arithmetic number, because the mean of its divisors is an integer number (61759928778229).

Almost surely, 2123519857556457 is an apocalyptic number.

It is an amenable number.

123519857556457 is a deficient number, since it is larger than the sum of its proper divisors (1).

123519857556457 is an equidigital number, since it uses as much as digits as its factorization.

123519857556457 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1587600000, while the sum is 73.

The spelling of 123519857556457 in words is "one hundred twenty-three trillion, five hundred nineteen billion, eight hundred fifty-seven million, five hundred fifty-six thousand, four hundred fifty-seven".