Base | Representation |
---|---|
bin | 10111000000100101… |
… | …11110001001100111 |
3 | 1011212220100121222200 |
4 | 23200102332021213 |
5 | 200244332113020 |
6 | 5401435425543 |
7 | 615055542213 |
oct | 134022761147 |
9 | 34786317880 |
10 | 12353004135 |
11 | 5269a4892a |
12 | 2488bb52b3 |
13 | 121b330204 |
14 | 85286b943 |
15 | 4c474e590 |
hex | 2e04be267 |
12353004135 has 24 divisors (see below), whose sum is σ = 21548267520. Its totient is φ = 6546301632.
The previous prime is 12353004127. The next prime is 12353004161. The reversal of 12353004135 is 53140035321.
12353004135 is a `hidden beast` number, since 123 + 530 + 0 + 4 + 1 + 3 + 5 = 666.
12353004135 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12353004135 - 23 = 12353004127 is a prime.
It is a super-2 number, since 2×123530041352 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12353004099 and 12353004108.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 867175 + ... + 881304.
It is an arithmetic number, because the mean of its divisors is an integer number (897844480).
Almost surely, 212353004135 is an apocalyptic number.
12353004135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12353004135 is a deficient number, since it is larger than the sum of its proper divisors (9195263385).
12353004135 is a wasteful number, since it uses less digits than its factorization.
12353004135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1748647 (or 1748644 counting only the distinct ones).
The product of its (nonzero) digits is 5400, while the sum is 27.
Adding to 12353004135 its reverse (53140035321), we get a palindrome (65493039456).
The spelling of 12353004135 in words is "twelve billion, three hundred fifty-three million, four thousand, one hundred thirty-five".
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