Base | Representation |
---|---|
bin | 10001111110011111011… |
… | …110010011001010100001 |
3 | 11101002121100110200112011 |
4 | 101332133132103022201 |
5 | 130214424232242423 |
6 | 2343300413232521 |
7 | 155151441246646 |
oct | 21763736231241 |
9 | 4332540420464 |
10 | 1235331134113 |
11 | 4369a024708a |
12 | 17b4b9a92741 |
13 | 8c6502ba71b |
14 | 43b0c9cddcd |
15 | 22201879b0d |
hex | 11f9f7932a1 |
1235331134113 has 32 divisors (see below), whose sum is σ = 1327363614720. Its totient is φ = 1147526714880.
The previous prime is 1235331134111. The next prime is 1235331134123. The reversal of 1235331134113 is 3114311335321.
It is not a de Polignac number, because 1235331134113 - 21 = 1235331134111 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is not an unprimeable number, because it can be changed into a prime (1235331134111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 29109156 + ... + 29151562.
It is an arithmetic number, because the mean of its divisors is an integer number (41480112960).
Almost surely, 21235331134113 is an apocalyptic number.
It is an amenable number.
1235331134113 is a deficient number, since it is larger than the sum of its proper divisors (92032480607).
1235331134113 is a wasteful number, since it uses less digits than its factorization.
1235331134113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 42817.
The product of its digits is 9720, while the sum is 31.
Adding to 1235331134113 its reverse (3114311335321), we get a palindrome (4349642469434).
The spelling of 1235331134113 in words is "one trillion, two hundred thirty-five billion, three hundred thirty-one million, one hundred thirty-four thousand, one hundred thirteen".
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