Base | Representation |
---|---|
bin | 10001111110011111011… |
… | …110010011001010100010 |
3 | 11101002121100110200112012 |
4 | 101332133132103022202 |
5 | 130214424232242424 |
6 | 2343300413232522 |
7 | 155151441246650 |
oct | 21763736231242 |
9 | 4332540420465 |
10 | 1235331134114 |
11 | 4369a0247090 |
12 | 17b4b9a92742 |
13 | 8c6502ba71c |
14 | 43b0c9cddd0 |
15 | 22201879b0e |
hex | 11f9f7932a2 |
1235331134114 has 16 divisors (see below), whose sum is σ = 2310229653696. Its totient is φ = 481297844400.
The previous prime is 1235331134111. The next prime is 1235331134123. The reversal of 1235331134114 is 4114311335321.
It is a super-2 number, since 2×12353311341142 (a number of 25 digits) contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (1235331134111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4010815217 + ... + 4010815524.
It is an arithmetic number, because the mean of its divisors is an integer number (144389353356).
Almost surely, 21235331134114 is an apocalyptic number.
1235331134114 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
1235331134114 is a deficient number, since it is larger than the sum of its proper divisors (1074898519582).
1235331134114 is a wasteful number, since it uses less digits than its factorization.
1235331134114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8021630761.
The product of its digits is 12960, while the sum is 32.
Adding to 1235331134114 its reverse (4114311335321), we get a palindrome (5349642469435).
The spelling of 1235331134114 in words is "one trillion, two hundred thirty-five billion, three hundred thirty-one million, one hundred thirty-four thousand, one hundred fourteen".
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