Base | Representation |
---|---|
bin | 111001100001111000… |
… | …0010111110111000011 |
3 | 102210212221120000120111 |
4 | 1303003300113313003 |
5 | 4011004042301201 |
6 | 132431030052151 |
7 | 11632342624252 |
oct | 1630360276703 |
9 | 383787500514 |
10 | 123543322051 |
11 | 48437a91456 |
12 | 1bb3a4aa057 |
13 | b85b311636 |
14 | 5d9db80799 |
15 | 33310bdb51 |
hex | 1cc3c17dc3 |
123543322051 has 2 divisors, whose sum is σ = 123543322052. Its totient is φ = 123543322050.
The previous prime is 123543321991. The next prime is 123543322061. The reversal of 123543322051 is 150223345321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 123543322051 - 211 = 123543320003 is a prime.
It is not a weakly prime, because it can be changed into another prime (123543322061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61771661025 + 61771661026.
It is an arithmetic number, because the mean of its divisors is an integer number (61771661026).
Almost surely, 2123543322051 is an apocalyptic number.
123543322051 is a deficient number, since it is larger than the sum of its proper divisors (1).
123543322051 is an equidigital number, since it uses as much as digits as its factorization.
123543322051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 123543322051 its reverse (150223345321), we get a palindrome (273766667372).
The spelling of 123543322051 in words is "one hundred twenty-three billion, five hundred forty-three million, three hundred twenty-two thousand, fifty-one".
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