12354403040113 has 4 divisors (see below), whose sum is σ = 12467746187380. Its totient is φ = 12241059892848.

The previous prime is 12354403040093. The next prime is 12354403040293. The reversal of 12354403040113 is 31104030445321.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 11101910794209 + 1252492245904 = 3331953^2 + 1119148^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12354403040113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12354403040813) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56671573470 + ... + 56671573687.

It is an arithmetic number, because the mean of its divisors is an integer number (3116936546845).

Almost surely, 2^{12354403040113} is an apocalyptic number.

It is an amenable number.

12354403040113 is a deficient number, since it is larger than the sum of its proper divisors (113343147267).

12354403040113 is a wasteful number, since it uses less digits than its factorization.

12354403040113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 113343147266.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 12354403040113 its reverse (31104030445321), we get a palindrome (43458433485434).

The spelling of 12354403040113 in words is "twelve trillion, three hundred fifty-four billion, four hundred three million, forty thousand, one hundred thirteen".