Base | Representation |
---|---|
bin | 1011001111000111101111… |
… | …0011011111101101110000 |
3 | 1121202001212120220220201010 |
4 | 2303301323303133231300 |
5 | 3104403304134240422 |
6 | 42135311233110520 |
7 | 2413401424110300 |
oct | 263617363375560 |
9 | 47661776826633 |
10 | 12354403040112 |
11 | 3a3352248a381 |
12 | 14764486b8440 |
13 | 6b8027546b93 |
14 | 309d5611b600 |
15 | 1665767adb0c |
hex | b3c7bcdfb70 |
12354403040112 has 120 divisors (see below), whose sum is σ = 37264259466000. Its totient is φ = 3516707217408.
The previous prime is 12354403040093. The next prime is 12354403040293. The reversal of 12354403040112 is 21104030445321.
It is a self number, because there is not a number n which added to its sum of digits gives 12354403040112.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 9130737 + ... + 10396112.
It is an arithmetic number, because the mean of its divisors is an integer number (310535495550).
Almost surely, 212354403040112 is an apocalyptic number.
12354403040112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
12354403040112 is an abundant number, since it is smaller than the sum of its proper divisors (24909856425888).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12354403040112 is a wasteful number, since it uses less digits than its factorization.
12354403040112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19527143 (or 19527130 counting only the distinct ones).
The product of its (nonzero) digits is 11520, while the sum is 30.
Adding to 12354403040112 its reverse (21104030445321), we get a palindrome (33458433485433).
The spelling of 12354403040112 in words is "twelve trillion, three hundred fifty-four billion, four hundred three million, forty thousand, one hundred twelve".
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