Base | Representation |
---|---|
bin | 1011001111000111101111… |
… | …0011011111110000100101 |
3 | 1121202001212120220220221211 |
4 | 2303301323303133300211 |
5 | 3104403304134242133 |
6 | 42135311233111421 |
7 | 2413401424110646 |
oct | 263617363376045 |
9 | 47661776826854 |
10 | 12354403040293 |
11 | 3a3352248a526 |
12 | 14764486b8571 |
13 | 6b8027546ca2 |
14 | 309d5611b6cd |
15 | 1665767adbcd |
hex | b3c7bcdfc25 |
12354403040293 has 2 divisors, whose sum is σ = 12354403040294. Its totient is φ = 12354403040292.
The previous prime is 12354403040093. The next prime is 12354403040327. The reversal of 12354403040293 is 39204030445321.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8222911823844 + 4131491216449 = 2867562^2 + 2032607^2 .
It is a cyclic number.
It is not a de Polignac number, because 12354403040293 - 217 = 12354402909221 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12354403040093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6177201520146 + 6177201520147.
It is an arithmetic number, because the mean of its divisors is an integer number (6177201520147).
Almost surely, 212354403040293 is an apocalyptic number.
It is an amenable number.
12354403040293 is a deficient number, since it is larger than the sum of its proper divisors (1).
12354403040293 is an equidigital number, since it uses as much as digits as its factorization.
12354403040293 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 311040, while the sum is 40.
The spelling of 12354403040293 in words is "twelve trillion, three hundred fifty-four billion, four hundred three million, forty thousand, two hundred ninety-three".
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