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12354810816217 is a prime number
BaseRepresentation
bin1011001111001001010000…
…0111000010011011011001
31121202002221000020002100211
42303302110013002123121
53104410123032104332
642135415521131121
72413414505130022
oct263622407023331
947662830202324
1012354810816217
113a33711686621
121476541189aa1
136b8090b7ba0c
14309d94347c49
1516659c4ab447
hexb3c941c26d9

12354810816217 has 2 divisors, whose sum is σ = 12354810816218. Its totient is φ = 12354810816216.

The previous prime is 12354810816193. The next prime is 12354810816223. The reversal of 12354810816217 is 71261801845321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12123516189456 + 231294626761 = 3481884^2 + 480931^2 .

It is an emirp because it is prime and its reverse (71261801845321) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12354810816217 is a prime.

It is a super-3 number, since 3×123548108162173 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (12354810876217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6177405408108 + 6177405408109.

It is an arithmetic number, because the mean of its divisors is an integer number (6177405408109).

Almost surely, 212354810816217 is an apocalyptic number.

It is an amenable number.

12354810816217 is a deficient number, since it is larger than the sum of its proper divisors (1).

12354810816217 is an equidigital number, since it uses as much as digits as its factorization.

12354810816217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 645120, while the sum is 49.

The spelling of 12354810816217 in words is "twelve trillion, three hundred fifty-four billion, eight hundred ten million, eight hundred sixteen thousand, two hundred seventeen".