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12387433 is a prime number
BaseRepresentation
bin101111010000…
…010001101001
3212022100100211
4233100101221
511132344213
61121301121
7210201652
oct57202151
925270324
1012387433
116aa0953
1241947a1
132749456
141906529
15114a53d
hexbd0469

12387433 has 2 divisors, whose sum is σ = 12387434. Its totient is φ = 12387432.

The previous prime is 12387377. The next prime is 12387451. The reversal of 12387433 is 33478321.

12387433 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8596624 + 3790809 = 2932^2 + 1947^2 .

It is a cyclic number.

It is not a de Polignac number, because 12387433 - 29 = 12386921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12387395 and 12387404.

It is not a weakly prime, because it can be changed into another prime (12387233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6193716 + 6193717.

It is an arithmetic number, because the mean of its divisors is an integer number (6193717).

Almost surely, 212387433 is an apocalyptic number.

It is an amenable number.

12387433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12387433 is an equidigital number, since it uses as much as digits as its factorization.

12387433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 12096, while the sum is 31.

The square root of 12387433 is about 3519.5785259034. The cubic root of 12387433 is about 231.3806869779.

The spelling of 12387433 in words is "twelve million, three hundred eighty-seven thousand, four hundred thirty-three".