Base | Representation |
---|---|
bin | 1011010001010111001011… |
… | …0010000001111100011011 |
3 | 1121212202020221201120022202 |
4 | 2310111302302001330123 |
5 | 3111021133012213442 |
6 | 42205120025040415 |
7 | 2416233526020014 |
oct | 264256262017433 |
9 | 47782227646282 |
10 | 12392906366747 |
11 | 3a4889061a585 |
12 | 14819b332610b |
13 | 6bb8525003aa |
14 | 30bb69a1000b |
15 | 16757bba6c32 |
hex | b4572c81f1b |
12392906366747 has 2 divisors, whose sum is σ = 12392906366748. Its totient is φ = 12392906366746.
The previous prime is 12392906366719. The next prime is 12392906366761. The reversal of 12392906366747 is 74766360929321.
12392906366747 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12392906366747 - 26 = 12392906366683 is a prime.
It is a super-3 number, since 3×123929063667473 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (12392906366047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6196453183373 + 6196453183374.
It is an arithmetic number, because the mean of its divisors is an integer number (6196453183374).
Almost surely, 212392906366747 is an apocalyptic number.
12392906366747 is a deficient number, since it is larger than the sum of its proper divisors (1).
12392906366747 is an equidigital number, since it uses as much as digits as its factorization.
12392906366747 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 123451776, while the sum is 65.
The spelling of 12392906366747 in words is "twelve trillion, three hundred ninety-two billion, nine hundred six million, three hundred sixty-six thousand, seven hundred forty-seven".
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