Base | Representation |
---|---|
bin | 10111000101101100… |
… | …10100011101000011 |
3 | 1011222212221011010021 |
4 | 23202312110131003 |
5 | 200341312344323 |
6 | 5410005314311 |
7 | 616115526244 |
oct | 134266243503 |
9 | 34885834107 |
10 | 12395824963 |
11 | 5291135845 |
12 | 249b405997 |
13 | 1227173992 |
14 | 858416ccb |
15 | 4c83ac05d |
hex | 2e2d94743 |
12395824963 has 2 divisors, whose sum is σ = 12395824964. Its totient is φ = 12395824962.
The previous prime is 12395824939. The next prime is 12395824981. The reversal of 12395824963 is 36942859321.
12395824963 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12395824963 - 221 = 12393727811 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12395824963.
It is not a weakly prime, because it can be changed into another prime (12395827963) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6197912481 + 6197912482.
It is an arithmetic number, because the mean of its divisors is an integer number (6197912482).
Almost surely, 212395824963 is an apocalyptic number.
12395824963 is a deficient number, since it is larger than the sum of its proper divisors (1).
12395824963 is an equidigital number, since it uses as much as digits as its factorization.
12395824963 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2799360, while the sum is 52.
The spelling of 12395824963 in words is "twelve billion, three hundred ninety-five million, eight hundred twenty-four thousand, nine hundred sixty-three".
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