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12397064153 is a prime number
BaseRepresentation
bin10111000101110110…
…00010111111011001
31011222222021002222012
423202323002333121
5200342122023103
65410052035305
7616132210115
oct134273027731
934888232865
1012397064153
115291901871
12249b902b35
1312274b8a26
1485865a745
154c85542d8
hex2e2ec2fd9

12397064153 has 2 divisors, whose sum is σ = 12397064154. Its totient is φ = 12397064152.

The previous prime is 12397064143. The next prime is 12397064161. The reversal of 12397064153 is 35146079321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11497843984 + 899220169 = 107228^2 + 29987^2 .

It is an emirp because it is prime and its reverse (35146079321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12397064153 - 24 = 12397064137 is a prime.

It is a super-2 number, since 2×123970641532 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12397064153.

It is not a weakly prime, because it can be changed into another prime (12397064143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6198532076 + 6198532077.

It is an arithmetic number, because the mean of its divisors is an integer number (6198532077).

Almost surely, 212397064153 is an apocalyptic number.

It is an amenable number.

12397064153 is a deficient number, since it is larger than the sum of its proper divisors (1).

12397064153 is an equidigital number, since it uses as much as digits as its factorization.

12397064153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 136080, while the sum is 41.

The spelling of 12397064153 in words is "twelve billion, three hundred ninety-seven million, sixty-four thousand, one hundred fifty-three".