124000512100121 has 2 divisors, whose sum is σ = 124000512100122. Its totient is φ = 124000512100120.

The previous prime is 124000512100099. The next prime is 124000512100133. The reversal of 124000512100121 is 121001215000421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111736823278096 + 12263688822025 = 10570564^2 + 3501955^2 .

It is a cyclic number.

It is not a de Polignac number, because 124000512100121 - 2³⁰ = 123999438358297 is a prime.

It is a super-3 number, since 3×124000512100121³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 124000512100093 and 124000512100102.

It is not a weakly prime, because it can be changed into another prime (124000512103121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62000256050060 + 62000256050061.

It is an arithmetic number, because the mean of its divisors is an integer number (62000256050061).

Almost surely, 2^{124000512100121} is an apocalyptic number.

It is an amenable number.

124000512100121 is a deficient number, since it is larger than the sum of its proper divisors (1).

124000512100121 is an equidigital number, since it uses as much as digits as its factorization.

124000512100121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 160, while the sum is 20.

Adding to 124000512100121 its reverse (121001215000421), we get a palindrome (245001727100542).

The spelling of 124000512100121 in words is "one hundred twenty-four trillion, five hundred twelve million, one hundred thousand, one hundred twenty-one".