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1240014114433 is a prime number
BaseRepresentation
bin10010000010110110100…
…110011100111010000001
311101112200201022201211201
4102002312212130322001
5130304022103130213
62345353221541201
7155405464030543
oct22026646347201
94345621281751
101240014114433
11438983705556
121803a6274801
138cc1856c7b3
144403492b693
15223c7a5e6dd
hex120b699ce81

1240014114433 has 2 divisors, whose sum is σ = 1240014114434. Its totient is φ = 1240014114432.

The previous prime is 1240014114407. The next prime is 1240014114467. The reversal of 1240014114433 is 3344114100421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1126924495489 + 113089618944 = 1061567^2 + 336288^2 .

It is an emirp because it is prime and its reverse (3344114100421) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1240014114433 - 25 = 1240014114401 is a prime.

It is a super-2 number, since 2×12400141144332 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1240014154433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620007057216 + 620007057217.

It is an arithmetic number, because the mean of its divisors is an integer number (620007057217).

Almost surely, 21240014114433 is an apocalyptic number.

It is an amenable number.

1240014114433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1240014114433 is an equidigital number, since it uses as much as digits as its factorization.

1240014114433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 1240014114433 its reverse (3344114100421), we get a palindrome (4584128214854).

The spelling of 1240014114433 in words is "one trillion, two hundred forty billion, fourteen million, one hundred fourteen thousand, four hundred thirty-three".