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12400400013 = 339227105373
BaseRepresentation
bin10111000110001111…
…10001011010001101
31012000012112120220120
423203013301122031
5200344000300023
65410251335153
7616202442501
oct134307613215
935005476816
1012400400013
115293780081
1224a0a514b9
1312280b6201
14858c88301
154c89b28e3
hex2e31f168d

12400400013 has 8 divisors (see below), whose sum is σ = 16534445088. Its totient is φ = 8266644144.

The previous prime is 12400400009. The next prime is 12400400017. The reversal of 12400400013 is 31000400421.

It is an interprime number because it is at equal distance from previous prime (12400400009) and next prime (12400400017).

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 12400400013 - 22 = 12400400009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12400399965 and 12400400001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12400400017) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 64995 + ... + 170367.

It is an arithmetic number, because the mean of its divisors is an integer number (2066805636).

Almost surely, 212400400013 is an apocalyptic number.

It is an amenable number.

12400400013 is a deficient number, since it is larger than the sum of its proper divisors (4134045075).

12400400013 is a wasteful number, since it uses less digits than its factorization.

12400400013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 144603.

The product of its (nonzero) digits is 96, while the sum is 15.

Adding to 12400400013 its reverse (31000400421), we get a palindrome (43400800434).

The spelling of 12400400013 in words is "twelve billion, four hundred million, four hundred thousand, thirteen".

Divisors: 1 3 39227 105373 117681 316119 4133466671 12400400013