Base | Representation |
---|---|
bin | 1011010001110011000110… |
… | …1000001011111111100001 |
3 | 1121220110121102100020222022 |
4 | 2310130301220023333201 |
5 | 3111132011204431032 |
6 | 42212355552151225 |
7 | 2416620360042425 |
oct | 264346150137741 |
9 | 47813542306868 |
10 | 12400403202017 |
11 | 3a50a88369906 |
12 | 1483345b38515 |
13 | 6bc478720aac |
14 | 30c27b53ab85 |
15 | 167869e11512 |
hex | b4731a0bfe1 |
12400403202017 has 2 divisors, whose sum is σ = 12400403202018. Its totient is φ = 12400403202016.
The previous prime is 12400403202013. The next prime is 12400403202053. The reversal of 12400403202017 is 71020230400421.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12154594486336 + 245808715681 = 3486344^2 + 495791^2 .
It is a cyclic number.
It is not a de Polignac number, because 12400403202017 - 22 = 12400403202013 is a prime.
It is not a weakly prime, because it can be changed into another prime (12400403202013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6200201601008 + 6200201601009.
It is an arithmetic number, because the mean of its divisors is an integer number (6200201601009).
Almost surely, 212400403202017 is an apocalyptic number.
It is an amenable number.
12400403202017 is a deficient number, since it is larger than the sum of its proper divisors (1).
12400403202017 is an equidigital number, since it uses as much as digits as its factorization.
12400403202017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2688, while the sum is 26.
Adding to 12400403202017 its reverse (71020230400421), we get a palindrome (83420633602438).
The spelling of 12400403202017 in words is "twelve trillion, four hundred billion, four hundred three million, two hundred two thousand, seventeen".
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