Search a number
-
+
1240110125151 = 3413370041717
BaseRepresentation
bin10010000010111100010…
…100101101000001011111
311101112221101222120210020
4102002330110231001133
5130304221143001101
62345410531443223
7155411041066302
oct22027424550137
94345841876706
101240110125151
11438a22921857
12180412456513
138cc32417581
14440435a0b39
15223d11c7136
hex120bc52d05f

1240110125151 has 4 divisors (see below), whose sum is σ = 1653480166872. Its totient is φ = 826740083432.

The previous prime is 1240110125147. The next prime is 1240110125207. The reversal of 1240110125151 is 1515210110421.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1240110125151 - 22 = 1240110125147 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1240110125131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 206685020856 + ... + 206685020861.

It is an arithmetic number, because the mean of its divisors is an integer number (413370041718).

Almost surely, 21240110125151 is an apocalyptic number.

1240110125151 is a deficient number, since it is larger than the sum of its proper divisors (413370041721).

1240110125151 is an equidigital number, since it uses as much as digits as its factorization.

1240110125151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 413370041720.

The product of its (nonzero) digits is 400, while the sum is 24.

Adding to 1240110125151 its reverse (1515210110421), we get a palindrome (2755320235572).

The spelling of 1240110125151 in words is "one trillion, two hundred forty billion, one hundred ten million, one hundred twenty-five thousand, one hundred fifty-one".

Divisors: 1 3 413370041717 1240110125151