Base | Representation |
---|---|
bin | 1011010001110101101101… |
… | …0110100110000011000101 |
3 | 1121220112102012120112020221 |
4 | 2310131123112212003011 |
5 | 3111134424411430341 |
6 | 42212553240224341 |
7 | 2416643620153633 |
oct | 264353326460305 |
9 | 47815365515227 |
10 | 12401103233221 |
11 | 3a5130752a69a |
12 | 148350046b0b1 |
13 | 6bc55a771441 |
14 | 30c3064c2353 |
15 | 1678ab5dced1 |
hex | b475b5a60c5 |
12401103233221 has 4 divisors (see below), whose sum is σ = 12408753514444. Its totient is φ = 12393452952000.
The previous prime is 12401103233201. The next prime is 12401103233263. The reversal of 12401103233221 is 12233230110421.
12401103233221 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 9205071048196 + 3196032185025 = 3033986^2 + 1787745^2 .
It is a cyclic number.
It is not a de Polignac number, because 12401103233221 - 221 = 12401101136069 is a prime.
It is a super-2 number, since 2×124011032332212 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12401103233201) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3825138180 + ... + 3825141421.
It is an arithmetic number, because the mean of its divisors is an integer number (3102188378611).
Almost surely, 212401103233221 is an apocalyptic number.
It is an amenable number.
12401103233221 is a deficient number, since it is larger than the sum of its proper divisors (7650281223).
12401103233221 is an equidigital number, since it uses as much as digits as its factorization.
12401103233221 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7650281222.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 12401103233221 its reverse (12233230110421), we get a palindrome (24634333343642).
The spelling of 12401103233221 in words is "twelve trillion, four hundred one billion, one hundred three million, two hundred thirty-three thousand, two hundred twenty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •