12401131331 has 2 divisors, whose sum is σ = 12401131332. Its totient is φ = 12401131330.

The previous prime is 12401131289. The next prime is 12401131361. The reversal of 12401131331 is 13313110421.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12401131331 - 2²² = 12396937027 is a prime.

It is a super-3 number, since 3×12401131331³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (12401131361) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6200565665 + 6200565666.

It is an arithmetic number, because the mean of its divisors is an integer number (6200565666).

Almost surely, 2^12401131331 is an apocalyptic number.

12401131331 is a deficient number, since it is larger than the sum of its proper divisors (1).

12401131331 is an equidigital number, since it uses as much as digits as its factorization.

12401131331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 12401131331 its reverse (13313110421), we get a palindrome (25714241752).

The spelling of 12401131331 in words is "twelve billion, four hundred one million, one hundred thirty-one thousand, three hundred thirty-one".