Base | Representation |
---|---|
bin | 11100001100100110100010… |
… | …111000101101110010111100 |
3 | 121021002100220100122211221122 |
4 | 130030212202320231302330 |
5 | 112223300142304422134 |
6 | 1115430003205050112 |
7 | 35056344126365621 |
oct | 3414464270556274 |
9 | 537070810584848 |
10 | 124011323514044 |
11 | 365719a817854a |
12 | 11aaa2853b6938 |
13 | 54272aa191575 |
14 | 228a274214348 |
15 | e50c447a602e |
hex | 70c9a2e2dcbc |
124011323514044 has 12 divisors (see below), whose sum is σ = 217020041733600. Its totient is φ = 62005597304448.
The previous prime is 124011323514017. The next prime is 124011323514097. The reversal of 124011323514044 is 440415323110421.
It is a junction number, because it is equal to n+sod(n) for n = 124011323513995 and 124011323514013.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11646404 + ... + 19587275.
It is an arithmetic number, because the mean of its divisors is an integer number (18085003477800).
Almost surely, 2124011323514044 is an apocalyptic number.
It is an amenable number.
124011323514044 is a deficient number, since it is larger than the sum of its proper divisors (93008718219556).
124011323514044 is a wasteful number, since it uses less digits than its factorization.
124011323514044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32226292 (or 32226290 counting only the distinct ones).
The product of its (nonzero) digits is 46080, while the sum is 35.
Adding to 124011323514044 its reverse (440415323110421), we get a palindrome (564426646624465).
The spelling of 124011323514044 in words is "one hundred twenty-four trillion, eleven billion, three hundred twenty-three million, five hundred fourteen thousand, forty-four".
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