Base | Representation |
---|---|
bin | 101111010011… |
… | …101001100011 |
3 | 212100001022121 |
4 | 233103221203 |
5 | 11133320001 |
6 | 1121445111 |
7 | 210260152 |
oct | 57235143 |
9 | 25301277 |
10 | 12401251 |
11 | 7000275 |
12 | 41a0797 |
13 | 2752825 |
14 | 190b599 |
15 | 114e6a1 |
hex | bd3a63 |
12401251 has 2 divisors, whose sum is σ = 12401252. Its totient is φ = 12401250.
The previous prime is 12401189. The next prime is 12401261. The reversal of 12401251 is 15210421.
12401251 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12401251 is a prime.
It is not a weakly prime, because it can be changed into another prime (12401261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6200625 + 6200626.
It is an arithmetic number, because the mean of its divisors is an integer number (6200626).
Almost surely, 212401251 is an apocalyptic number.
12401251 is a deficient number, since it is larger than the sum of its proper divisors (1).
12401251 is an equidigital number, since it uses as much as digits as its factorization.
12401251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 16.
The square root of 12401251 is about 3521.5409979155. The cubic root of 12401251 is about 231.4666889298.
Adding to 12401251 its reverse (15210421), we get a palindrome (27611672).
The spelling of 12401251 in words is "twelve million, four hundred one thousand, two hundred fifty-one".
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