124013213143 has 4 divisors (see below), whose sum is σ = 124532097120. Its totient is φ = 123494329168.

The previous prime is 124013213081. The next prime is 124013213171. The reversal of 124013213143 is 341312310421.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-124013213143 is a prime.

It is a super-2 number, since 2×124013213143² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (124013210143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 259441630 + ... + 259442107.

It is an arithmetic number, because the mean of its divisors is an integer number (31133024280).

Almost surely, 2^124013213143 is an apocalyptic number.

124013213143 is a deficient number, since it is larger than the sum of its proper divisors (518883977).

124013213143 is an equidigital number, since it uses as much as digits as its factorization.

124013213143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 518883976.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 124013213143 its reverse (341312310421), we get a palindrome (465325523564).

The spelling of 124013213143 in words is "one hundred twenty-four billion, thirteen million, two hundred thirteen thousand, one hundred forty-three".