1240132344403 has 2 divisors, whose sum is σ = 1240132344404. Its totient is φ = 1240132344402.

The previous prime is 1240132344371. The next prime is 1240132344419. The reversal of 1240132344403 is 3044432310421.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1240132344403 - 2⁵ = 1240132344371 is a prime.

It is not a weakly prime, because it can be changed into another prime (1240132344103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620066172201 + 620066172202.

It is an arithmetic number, because the mean of its divisors is an integer number (620066172202).

Almost surely, 2^{1240132344403} is an apocalyptic number.

1240132344403 is a deficient number, since it is larger than the sum of its proper divisors (1).

1240132344403 is an equidigital number, since it uses as much as digits as its factorization.

1240132344403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 1240132344403 its reverse (3044432310421), we get a palindrome (4284564654824).

The spelling of 1240132344403 in words is "one trillion, two hundred forty billion, one hundred thirty-two million, three hundred forty-four thousand, four hundred three".