Base | Representation |
---|---|
bin | 10010000010111101101… |
… | …001011101101011010011 |
3 | 11101112222221210110001020 |
4 | 102002331221131223103 |
5 | 130304242340011111 |
6 | 2345413044010523 |
7 | 155411431000653 |
oct | 22027551355323 |
9 | 4345887713036 |
10 | 1240132344531 |
11 | 438a34418583 |
12 | 180419990a43 |
13 | 8cc36bc6c32 |
14 | 44046506363 |
15 | 223d3115906 |
hex | 120bda5dad3 |
1240132344531 has 48 divisors (see below), whose sum is σ = 1779543379680. Its totient is φ = 767968542720.
The previous prime is 1240132344509. The next prime is 1240132344571. The reversal of 1240132344531 is 1354432310421.
It is not a de Polignac number, because 1240132344531 - 27 = 1240132344403 is a prime.
It is a super-2 number, since 2×12401323445312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1240132344492 and 1240132344501.
It is not an unprimeable number, because it can be changed into a prime (1240132344571) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 24261741 + ... + 24312801.
It is an arithmetic number, because the mean of its divisors is an integer number (37073820410).
Almost surely, 21240132344531 is an apocalyptic number.
1240132344531 is a deficient number, since it is larger than the sum of its proper divisors (539411035149).
1240132344531 is a wasteful number, since it uses less digits than its factorization.
1240132344531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51464 (or 51447 counting only the distinct ones).
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 1240132344531 its reverse (1354432310421), we get a palindrome (2594564654952).
The spelling of 1240132344531 in words is "one trillion, two hundred forty billion, one hundred thirty-two million, three hundred forty-four thousand, five hundred thirty-one".
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