Base | Representation |
---|---|
bin | 10010000010111110010… |
… | …111001011110110010101 |
3 | 11101120000210100101012102 |
4 | 102002332113023312111 |
5 | 130304303422031013 |
6 | 2345414152531445 |
7 | 155411634610262 |
oct | 22027627136625 |
9 | 4346023311172 |
10 | 1240144330133 |
11 | 438a40164535 |
12 | 1804219b0b85 |
13 | 8cc395324c7 |
14 | 44047d46269 |
15 | 223d41d1d58 |
hex | 120be5cbd95 |
1240144330133 has 4 divisors (see below), whose sum is σ = 1243332362220. Its totient is φ = 1236956298048.
The previous prime is 1240144330049. The next prime is 1240144330153. The reversal of 1240144330133 is 3310334410421.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 880440669124 + 359703661009 = 938318^2 + 599753^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1240144330133 is a prime.
It is a super-2 number, since 2×12401443301332 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1240144330096 and 1240144330105.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1240144330153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1594015460 + ... + 1594016237.
It is an arithmetic number, because the mean of its divisors is an integer number (310833090555).
Almost surely, 21240144330133 is an apocalyptic number.
It is an amenable number.
1240144330133 is a deficient number, since it is larger than the sum of its proper divisors (3188032087).
1240144330133 is an equidigital number, since it uses as much as digits as its factorization.
1240144330133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3188032086.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 1240144330133 its reverse (3310334410421), we get a palindrome (4550478740554).
The spelling of 1240144330133 in words is "one trillion, two hundred forty billion, one hundred forty-four million, three hundred thirty thousand, one hundred thirty-three".
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