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1240145204497 is a prime number
BaseRepresentation
bin10010000010111110011…
…010100001010100010001
311101120000211222210121021
4102002332122201110101
5130304304133020442
62345414223355441
7155411645211403
oct22027632412421
94346024883537
101240145204497
11438a40701451
12180422152b81
138cc3977a494
14440480d2b73
15223d4305e67
hex120be6a1511

1240145204497 has 2 divisors, whose sum is σ = 1240145204498. Its totient is φ = 1240145204496.

The previous prime is 1240145204423. The next prime is 1240145204513. The reversal of 1240145204497 is 7944025410421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 659098798801 + 581046405696 = 811849^2 + 762264^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1240145204497 is a prime.

It is not a weakly prime, because it can be changed into another prime (1240185204497) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620072602248 + 620072602249.

It is an arithmetic number, because the mean of its divisors is an integer number (620072602249).

Almost surely, 21240145204497 is an apocalyptic number.

It is an amenable number.

1240145204497 is a deficient number, since it is larger than the sum of its proper divisors (1).

1240145204497 is an equidigital number, since it uses as much as digits as its factorization.

1240145204497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 322560, while the sum is 43.

The spelling of 1240145204497 in words is "one trillion, two hundred forty billion, one hundred forty-five million, two hundred four thousand, four hundred ninety-seven".