Base | Representation |
---|---|
bin | 1011010001110111101011… |
… | …0101001001100010001011 |
3 | 1121220120210000021221212212 |
4 | 2310131322311021202023 |
5 | 3111142020110232322 |
6 | 42213121503255335 |
7 | 2416662662026613 |
oct | 264357265114213 |
9 | 47816700257785 |
10 | 12401631336587 |
11 | 3a51558641559 |
12 | 14836292aa54b |
13 | 6bc612cb613c |
14 | 30c3566b1a43 |
15 | 1678dcb580e2 |
hex | b477ad4988b |
12401631336587 has 2 divisors, whose sum is σ = 12401631336588. Its totient is φ = 12401631336586.
The previous prime is 12401631336503. The next prime is 12401631336617. The reversal of 12401631336587 is 78563313610421.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12401631336587 - 28 = 12401631336331 is a prime.
It is not a weakly prime, because it can be changed into another prime (12401631536587) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6200815668293 + 6200815668294.
It is an arithmetic number, because the mean of its divisors is an integer number (6200815668294).
Almost surely, 212401631336587 is an apocalyptic number.
12401631336587 is a deficient number, since it is larger than the sum of its proper divisors (1).
12401631336587 is an equidigital number, since it uses as much as digits as its factorization.
12401631336587 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2177280, while the sum is 50.
The spelling of 12401631336587 in words is "twelve trillion, four hundred one billion, six hundred thirty-one million, three hundred thirty-six thousand, five hundred eighty-seven".
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