Base | Representation |
---|---|
bin | 111001110000000101… |
… | …1100011110111010001 |
3 | 102212010011220111102211 |
4 | 1303200023203313101 |
5 | 4012443133224103 |
6 | 132550223312121 |
7 | 11650223254426 |
oct | 1634013436721 |
9 | 385104814384 |
10 | 124020211153 |
11 | 486621a3283 |
12 | 2005214b641 |
13 | b906064337 |
14 | 600723bd4d |
15 | 335cdbe36d |
hex | 1ce02e3dd1 |
124020211153 has 2 divisors, whose sum is σ = 124020211154. Its totient is φ = 124020211152.
The previous prime is 124020211123. The next prime is 124020211157. The reversal of 124020211153 is 351112020421.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 118166125009 + 5854086144 = 343753^2 + 76512^2 .
It is a cyclic number.
It is not a de Polignac number, because 124020211153 - 25 = 124020211121 is a prime.
It is not a weakly prime, because it can be changed into another prime (124020211157) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62010105576 + 62010105577.
It is an arithmetic number, because the mean of its divisors is an integer number (62010105577).
Almost surely, 2124020211153 is an apocalyptic number.
It is an amenable number.
124020211153 is a deficient number, since it is larger than the sum of its proper divisors (1).
124020211153 is an equidigital number, since it uses as much as digits as its factorization.
124020211153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 480, while the sum is 22.
Adding to 124020211153 its reverse (351112020421), we get a palindrome (475132231574).
The spelling of 124020211153 in words is "one hundred twenty-four billion, twenty million, two hundred eleven thousand, one hundred fifty-three".
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