Base | Representation |
---|---|
bin | 10111000110011100… |
… | …00001110110110001 |
3 | 1012000022121220212202 |
4 | 23203032001312301 |
5 | 200344410241431 |
6 | 5410350432545 |
7 | 616222413503 |
oct | 134316016661 |
9 | 35008556782 |
10 | 12402040241 |
11 | 52946a0438 |
12 | 24a1502755 |
13 | 122853b966 |
14 | 859193d73 |
15 | 4c8bd88cb |
hex | 2e3381db1 |
12402040241 has 2 divisors, whose sum is σ = 12402040242. Its totient is φ = 12402040240.
The previous prime is 12402040237. The next prime is 12402040279. The reversal of 12402040241 is 14204020421.
12402040241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10706247841 + 1695792400 = 103471^2 + 41180^2 .
It is a cyclic number.
It is not a de Polignac number, because 12402040241 - 22 = 12402040237 is a prime.
It is not a weakly prime, because it can be changed into another prime (12402040201) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6201020120 + 6201020121.
It is an arithmetic number, because the mean of its divisors is an integer number (6201020121).
Almost surely, 212402040241 is an apocalyptic number.
It is an amenable number.
12402040241 is a deficient number, since it is larger than the sum of its proper divisors (1).
12402040241 is an equidigital number, since it uses as much as digits as its factorization.
12402040241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 512, while the sum is 20.
Adding to 12402040241 its reverse (14204020421), we get a palindrome (26606060662).
The spelling of 12402040241 in words is "twelve billion, four hundred two million, forty thousand, two hundred forty-one".
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