12403000111 has 8 divisors (see below), whose sum is σ = 12834655200. Its totient is φ = 11971609440.

The previous prime is 12403000069. The next prime is 12403000117. The reversal of 12403000111 is 11100030421.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12403000111 - 2¹³ = 12402991919 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12403000091 and 12403000100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12403000117) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31821 + ... + 160681.

It is an arithmetic number, because the mean of its divisors is an integer number (1604331900).

Almost surely, 2^12403000111 is an apocalyptic number.

12403000111 is a deficient number, since it is larger than the sum of its proper divisors (431655089).

12403000111 is a wasteful number, since it uses less digits than its factorization.

12403000111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 132209.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 12403000111 its reverse (11100030421), we get a palindrome (23503030532).

The spelling of 12403000111 in words is "twelve billion, four hundred three million, one hundred eleven", and thus it is an aban number.