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12403213131 = 343269357431
BaseRepresentation
bin10111000110100101…
…00000001101001011
31012000101211111210010
423203102200031023
5200400210310011
65410431523003
7616235400141
oct134322401513
935011744703
1012403213131
115295321671
1224a1989463
13122885c78a
148593bb591
154c8d6b1a6
hex2e34a034b

12403213131 has 16 divisors (see below), whose sum is σ = 16985168640. Its totient is φ = 8046464160.

The previous prime is 12403213103. The next prime is 12403213139. The reversal of 12403213131 is 13131230421.

It is not a de Polignac number, because 12403213131 - 25 = 12403213099 is a prime.

It is a super-2 number, since 2×124032131312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12403213098 and 12403213107.

It is not an unprimeable number, because it can be changed into a prime (12403213139) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 144015 + ... + 213416.

It is an arithmetic number, because the mean of its divisors is an integer number (1061573040).

Almost surely, 212403213131 is an apocalyptic number.

12403213131 is a deficient number, since it is larger than the sum of its proper divisors (4581955509).

12403213131 is a wasteful number, since it uses less digits than its factorization.

12403213131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 357746.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 12403213131 its reverse (13131230421), we get a palindrome (25534443552).

The spelling of 12403213131 in words is "twelve billion, four hundred three million, two hundred thirteen thousand, one hundred thirty-one".

Divisors: 1 3 43 129 269 807 11567 34701 357431 1072293 15369533 46108599 96148939 288446817 4134404377 12403213131