Base | Representation |
---|---|
bin | 111001110000100000… |
… | …0101010111111110001 |
3 | 102212011011002211222212 |
4 | 1303201000222333301 |
5 | 4013010214242001 |
6 | 132551441541505 |
7 | 11650452513011 |
oct | 1634100527761 |
9 | 385134084885 |
10 | 124034134001 |
11 | 4866a042768 |
12 | 20056944895 |
13 | b908bca5cb |
14 | 6009023c41 |
15 | 335e21e7bb |
hex | 1ce102aff1 |
124034134001 has 2 divisors, whose sum is σ = 124034134002. Its totient is φ = 124034134000.
The previous prime is 124034133983. The next prime is 124034134013. The reversal of 124034134001 is 100431430421.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 86562466225 + 37471667776 = 294215^2 + 193576^2 .
It is a cyclic number.
It is not a de Polignac number, because 124034134001 - 226 = 123967025137 is a prime.
It is not a weakly prime, because it can be changed into another prime (124034124001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62017067000 + 62017067001.
It is an arithmetic number, because the mean of its divisors is an integer number (62017067001).
Almost surely, 2124034134001 is an apocalyptic number.
It is an amenable number.
124034134001 is a deficient number, since it is larger than the sum of its proper divisors (1).
124034134001 is an equidigital number, since it uses as much as digits as its factorization.
124034134001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 124034134001 its reverse (100431430421), we get a palindrome (224465564422).
The spelling of 124034134001 in words is "one hundred twenty-four billion, thirty-four million, one hundred thirty-four thousand, one".
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