12403422003231 has 48 divisors (see below), whose sum is σ = 21157760452608. Its totient is φ = 6851970273600.

The previous prime is 12403422003229. The next prime is 12403422003331. The reversal of 12403422003231 is 13230022430421.

12403422003231 is a `hidden beast` number, since 1 + 2 + 4 + 0 + 3 + 422 + 0 + 0 + 3 + 231 = 666.

It is not a de Polignac number, because 12403422003231 - 2¹ = 12403422003229 is a prime.

It is a super-2 number, since 2×12403422003231² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12403422003195 and 12403422003204.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12403422003331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1373956 + ... + 5166681.

It is an arithmetic number, because the mean of its divisors is an integer number (440786676096).

Almost surely, 2^{12403422003231} is an apocalyptic number.

12403422003231 is a deficient number, since it is larger than the sum of its proper divisors (8754338449377).

12403422003231 is a wasteful number, since it uses less digits than its factorization.

12403422003231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6541652 (or 6541649 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 12403422003231 its reverse (13230022430421), we get a palindrome (25633444433652).

The spelling of 12403422003231 in words is "twelve trillion, four hundred three billion, four hundred twenty-two million, three thousand, two hundred thirty-one".